ouhwAfEnIwbvUIhGPzy
Á¶È¸ : 20        ÀÛ¼ºÀÚ : easy car insurance q     [ iabuhhr7y2@mail.com ]  [ http://rinkontiki.com/WA/easy-car-insurance-quotes-washingto ]
Hmmm. I do not know the recommended way to do it but the way would be something like this (the dirty way):$sql = "SELECT a.*, b.* FROM database1.table1 a LEFT JOIN database2.table2 b ON b.id=a.ass_idWHERE a.status=".$this->_db->quote('A'); return $this->_db->fetchAll($sql);It is basically just a table join between two tables. The SQL output would be something like:SELECT a.*, b.* FROM database1.table1 a LEFT JOIN database2.table2 b ON b.id=a.ass_id WHERE a.STATUS = "A"
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